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2x^2/5-40x=0
We multiply all the terms by the denominator
2x^2-40x*5=0
Wy multiply elements
2x^2-200x=0
a = 2; b = -200; c = 0;
Δ = b2-4ac
Δ = -2002-4·2·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-200}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+200}{2*2}=\frac{400}{4} =100 $
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